iz^2+(1+i)z+1=0

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Solution for iz^2+(1+i)z+1=0 equation:


Simplifying
iz2 + (1 + i) * z + 1 = 0

Reorder the terms for easier multiplication:
iz2 + z(1 + i) + 1 = 0
iz2 + (1 * z + i * z) + 1 = 0

Reorder the terms:
iz2 + (iz + 1z) + 1 = 0
iz2 + (iz + 1z) + 1 = 0

Reorder the terms:
1 + iz + iz2 + 1z = 0

Solving
1 + iz + iz2 + 1z = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + iz + iz2 + -1 + 1z = 0 + -1

Reorder the terms:
1 + -1 + iz + iz2 + 1z = 0 + -1

Combine like terms: 1 + -1 = 0
0 + iz + iz2 + 1z = 0 + -1
iz + iz2 + 1z = 0 + -1

Combine like terms: 0 + -1 = -1
iz + iz2 + 1z = -1

Add '-1z' to each side of the equation.
iz + iz2 + 1z + -1z = -1 + -1z

Combine like terms: 1z + -1z = 0
iz + iz2 + 0 = -1 + -1z
iz + iz2 = -1 + -1z

Reorder the terms:
1 + iz + iz2 + z = -1 + -1z + 1 + z

Reorder the terms:
1 + iz + iz2 + z = -1 + 1 + -1z + z

Combine like terms: -1 + 1 = 0
1 + iz + iz2 + z = 0 + -1z + z
1 + iz + iz2 + z = -1z + z

Combine like terms: -1z + z = 0
1 + iz + iz2 + z = 0

The solution to this equation could not be determined.

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